Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let f(x) =
& x ∈ 
Then the interval in which at least one root of equaiton lie
+
+
= 0
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(a, d)
f '(x) = 
Let g(x) = sin x – x cos x
g'(x) = cos x + x sin x – cos x
g'(x) > 0 ∀ x ∈ (0, π /2)
g(x)
g(0) < g(x)
0 < sin x – x cos x
∴ f '(x) > 0
f(x) Let α = π /12, β = π /4, r = 5 π /12
⇒ f( α ) < f( β ) < f(r)
Let H(x) = 2 (x –f( β )) (x – f(r)) + 3 (x – f( α )) (x – f(r)) + 4 (x – f( α )) (x – f( β ))
H (f(r)) > 0, H(f( β )) < 0, H(f(r)) > 0
⇒ one root in (f(r), f( β ))
and other in (f( β ), f(r))
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