Match the statements given in Column-I with the intervals/union of intervals given in Column-II
Column-I Column-II
is (p) (– ∞ , –1) ∪ (1, ∞ )
is (q) (– ∞ , 0) ∪ (0, ∞ )
, (r) [2, ∞ ) then the set 
is
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
Re 
= Re 
= Re 
= Re (–1/y) = 
= –1 ≤ y ≤ 1 = 
≥ 1 or 
≤ – 1
Alternate
Re 
= Re 
= Re 
= Re 
= Re 
= Re 
as pwafd –1 ≤ sin θ ≤ 1
(– ∞ , 0 ) ∪ (0, ∞ )
–1 ≤ 
≤ 1 ⇒ –1 ≤ 
≤ 1
⇒ –1 ≤ 
≤ 1 ⇒ 0 ≤ 
∩ 
– 1 ≤ 0
⇒ 0 ≤ 
∩ 
≤ 0 ⇒ 0 ≤ 
∩ 
≥ 0
⇒ t ∈ (– ∞ , –9] ∪ [–1 , 1] ∪ [9, ∞ ) ⇒ x ∈ (– ∞ , 0) ∪ [2 , ∞ )
⇒ t ∈ (– ∞ , –9] ∪ [–1 , 1] ∪ [9, ∞ ) ⇒ x ∈ (– ∞ , 0) ∪ [2 , ∞ )
f( θ ) = 2 sec 2 θ
⇒ f( θ ) ≥ 2
⇒ f( θ ) ∈ [2, ∞ )
f(x) = x 3/2 (3x – 10)
⇒ f ’ (x) = x 3/2 3 + 
x 1/2 (3x –10)
as f ’ (x) ≥ 0
⇒ 
≥ 0
⇒ 3x + 
– 15 ≥ 0
⇒ 
– 15 ≥ 0
⇒ x ≥ 2
⇒ x ∈ [2, ∞ )
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