Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If (1+x) 15 = C 0 + C 1 . x + C 2 . x 2 +.... + C 15 . x 15 , then find the value of : C 2 + 2C 3 + 3C 4 +.... + 14C 15
Text Solution
Verified by ExpertsThe correct answer is:
212993
(212993)
(1 + x) 15 = C 0 + C 1 x + .........+ C 15 x 15
Divide by x & then differentiating both side
=
+ C 1 + C 2 x + C 3 x 2 + .......+ C 15 x 14
.
15(1 + x) 14 –
= –
+ C 2 + .....+ 14 C 15 x 13
Put x = 1 then C 2 + 2C 3 + .........+ 14C 15 = 15.2 14 – 2 15 + 1
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
In the expansion of the term containing same powers of a & b is
Consider the following statements :
S 1 : Number of dissimilar terms in the expansion of (1 + x + x…
If then the value of k is :
The co-efficient of x 5 in the expansion of (1 + x) 21 + (1 + x) 22 +....... + (1 + x) 30 is :
The coefficient of x 52 in the expansion (x – 3) 100–m . 2 m is :
The sum of the coefficients of all the integral powers of x in the expansion of is: