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CGP EDU Academic Team
Published on: August 12, 2026
A variable circle passes through the point A (a,
Text Solution
Verified by ExpertsThe correct answer is:
4
(4)Equation of circle whose diameter's end points are (a, and (h, k)
(x – a) (x – h) + (y – (y – k) = 0
x 2 + y 2 – x(a + h) – y(b + k) + ah + bk = 0
it touches x-axis.

Hence g 2 = c ⇒
= ah + bk ⇒ (h – a) 2 = 4bk
∴ Locus of (h, k) is (x – a) 2 = 4by.
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