Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Tangents are drawn to the circle x 2 + y 2 = 50 from a point ‘P’ lying on the x-axis. These tangents meet the y-axis at points ‘P 1 ’ and ‘P 2 ’. Possible coordinates of ‘P’ so that area of triangle PP 1 P 2 is minimum, is/are
A
(10, 0)
B
(10 
, 0)
, 0)
C
(–10, 0)
D
(– 10 
, 0)
, 0)
Text Solution
Verified by ExpertsThe correct answer is:
A
(a,c)OP = 5 
sec θ , OP 1 = 5 
cosec θ
area ( Δ PP 1 P 2 ) = 
, area ( Δ PP 1 P 2 ) min = 100
⇒ θ = π /4 ⇒ OP = 10 ⇒ P = (10, 0), (– 10, 0)
Hence , are correct
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