Published by:
CGP EDU Academic Team
Published on: August 13, 2026
A circle is described to pass through the origin and to touch the lines 
. Prove that the radius of the circle is a root of the equation 
Text Solution
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CHECK THE SOLUTION.
Let the centre of the circle be (h, k) and radius equal to ‘r’
…..(i)
and 
= r ⇒ 2 – h – k = r 
.....(ii)
and h = 1 – r.......(iii)
put h = 1 – r in (ii), we get k = r (1 – 
) + 1
Now put the values of h and k in (i), we get
hence radius i.e. 
is the root of the equation 
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