Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The lines 
and 
touch a circle 
of diameter 6 unit. If the centre of 
lies in the first quadrant, find the equation of the circle 
which is concentric with 
and cuts of intercepts of length 8 on these lines.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Centre of 
lies over angle bisector of 
Equations of angle bisectors are
= ± 
⇒ x = 5 or y = – 
Since centre lies in first quadrant so it should be on x = 5.
So let centre be (5, α ) ⇒ 3 = 
⇒ α = 2, – 
From the figure r = 
. But α ≠ – 
so α = 2.
So equation of cirlce 
is
.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Column – I Column – II
[16JM110516]
If , , & are four distinct points on a circle of radius 4 units, then abcd is equal to:
From the point A (0 , 3) on the circle x² + 4x + (y − 3)² = 0 a chord AB is drawn & extended to a p…
If tangent at (1, 2) to the circle intersects the circle at and tangents at A & B to the second …
A circle passes through point touches the line pair . Centre of circle lies inside the circle Co…
The length of the tangents from any point on the circle to the two circles and are in the ratio