Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The locus of a point so that sum of its distance from two given perpendicular lines is equal to 2 unit in first quadrant, is
Text Solution
Verified by ExpertsThe correct answer is:
B
We take the coordinate axes as two perpendicular lines. Let
be the required point.
From
, we draw PM and PN perpendicular to OX and OY respectively.
Given,
......(i)
But, 
Hence from (i), 
Thus locus of
is 
which is a straight line.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The vertex of an equilateral triangle is (2, –1) and the equation of its base is . The length of i…
The area enclosed within the curve is
The area of the rhombus enclosed by the lines ax ± by ± c = 0 is
If the coordinates of the vertices of the triangle ABC be (–1, 6), (–3, –9) and (5, –8) respectivel…
In an isosceles triangle ABC , the coordinates of the point B and C on the base BC are respectively…
A square of side a lies above the x -axis and has one vertex at the origin. The side passing throug…