Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If for the complex numbers z satisfying |z − 2 − 2i| ≤ 1, the maximum value of |3iz + 6| is attained at a + ib, then a + b is equal to.
Text Solution
Verified by ExpertsThe correct answer is:
5
(5)
|z − 2 − 2i| ≤ 1
|x + iy− 2 − 2i| ≤ 1
|(x − 2) + i(y − 2)| ≤ 1
(x − 2) 2 + (y − 2) 2 ≤ 1
|3iz + 6| max at a + ib
|3i|z + 
∣
3|z − 2i| max
From Figure maximum distance at 3+2i
a + ib = 3 + 2i = a + b = 3 + 2 = 5
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