Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If
, then for y=1, the value of x lies in the interval:
Text Solution
Verified by ExpertsThe correct answer is:
A


⇒ ℓn |y + 2 y | = x + c
x = 0; y = 0 ⇒ c = 0
⇒ x = ℓn |y + 2 y |
⇒ y = 1, x = ℓn3
∵ 3 ∈ (e, e 2 ) ⇒ x ∈ (1, 2)
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