Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Let us consider a curve, y = f(x) passing through the point (−2, 2) and the slope of the tangent to the curve at any point (x, f(x)) is given by f(x) + xf ’ (x) = x 2 .Then :
Text Solution
Verified by ExpertsThe correct answer is:
C
(given)

If 
Solution of DE
⇒ y ⋅ x = ∫ x ⋅ xdx

Passes through (−2, 2), so
−12 = −8 + c ⇒ c = −4
∴ 3xy = x 3 – 4
ie. 3x ⋅ f(x) = x 3 − 4
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