Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Let A be the set of all points (α, β) such that the area of triangle formed by the points (5, 6), (3, 2) and (α, β) is 12 square units. Then the least possible length of a line segment joining the origin to a point in A, is :
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
4α − 2β = ±24 + 8
⇒ 4α − 2β = +24 + 8 ⇒ 2α − β = 16
2x − y − 16 = 0 ...(1)
⇒ 4α − 2β = −24 + 8 ⇒ 2α − β = −8
2x − y + 8 = 0...(2)
perpendicular distance of (1) from (0,0)
perpendicular distance of (2) from (0,0)is
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