Published by:
CGP EDU Academic Team
Published on: August 14, 2026
On the ellipse
let P be a point in the second quadrant such that the tangent at P to the ellipse is perpendicular to the line x + 2y = 0. Let S and S’ be the foci of the ellipse and be its eccentricity. If A is the area of the triangle SPS' then, the value of (5-e 2 ). A is :
Text Solution
Verified by ExpertsThe correct answer is:
A

Equation of tangent: y = 2x + 6
At P
∴ P(−8/3, 2/3)

S& S’= (−2, 0)&(2, 0)
Area of 


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