Maths Statistics ( Measures of Central Tendency and Dispersion ) JEE Main 2021 Numeric Response
Published on: August 14, 2026

An online exam is attempted by 50 candidates out of which 20 are boys. The average marks obtained by boys is 12 with a variance 2. The variance of marks obtained by 30 girls is also 2. The average marks of all 50 candidates is 15. If μ is the average marks of girls and σ 2 is the variance of marks of 50 candidates, then μ + σ 2 is equal to .

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The correct answer is:
25

(25)

(variance of boys) n 1 =no. of boys

n 2 =no. of girls

variance of combined series

σ 2 = 8

⇒ μ + σ 2 = 17 + 8 = 25

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