The square of the distance of the point of intersection of …

Maths Coordinate Geometry (3D) JEE Main 2021 - ( Three Dimensional Geometry ) Numeric Response

Published on: August 14, 2026

The square of the distance of the point of intersection of the line and the plane 2x − y + z = 6 from the point ( − 1, − 1, 2) is .

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The correct answer is:

(61)

x = 2λ + 1, y = 3λ + 2, z = 6λ − 1

for point of intersection of line \& plane

2(2λ + 1) − (3λ + 2) + (6λ − 1) = 6

7λ = 7 ⇒ λ = 1

point :(3, 5, 5)

( distance ) 2 = (3 + 1) 2 + (5 + 1) 2 + (5 − 2) 2

= 16 + 36 + 9 = 61

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