In column A different equations of parabolas are given and in column B their one of the parameters is given match them. Column-IColumn-II(i) Vertex of parabola6x[A] x2 – 6x – 4y + 3 = 0(ii) Focus of parabola [Β] y2 – 4y – 3x – 2 = 0(iii) Mid point of vertex& Focus of parabola(y – 2)2 = 2 (x – 1)[C] (iv) Point at which normal drawn on parabola y2 = 4x, makes equal angle with axis[D] (1, 2)

In column A different equations of parabolas are given and …

Maths Conic Sections Parabola Matrix Match Questions

Published on: August 13, 2026

In column A different equations of parabolas are given and in column B their one of the parameters is given match them.

Column-I	Column-II
(i) Vertex of parabola6x	[A] x2 – 6x – 4y + 3 = 0
(ii) Focus of parabola	[Β] y2 – 4y – 3x – 2 = 0
(iii) Mid point of vertex& Focus of parabola(y – 2)2 = 2 (x – 1)	[C]
(iv) Point at which normal drawn on parabola y2 = 4x, makes equal angle with axis	[D] (1, 2)

Correct Matrix Matching

Verified by Experts

The correct answer is:

(i) [C]; (ii) [B]; (iii) [A]; (iv) [D]; (i) (ii); (iv) (1,2)

Ans.

(i) [C]

(ii) [B]

(iii) [A]

(iv) [D]

Sol.

(i)

(ii)

(iii) x 2 – 6x – 4y + 3 = 0

(iv) (1,2)

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