The correct answer is C. Here, = Now, 2 ≤ ≤ x 2 + 2 0 ⇒ ⇒ – < 0 ⇒ ⇒ < 1 ⇒ ⇒

Range of sin -1 is:

Maths Functions, Limits, Continuity and Differentiability Functions Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 12, 2026

Range of sin -1 is:

[0, π π /2]

(0, π π /6)

[ π π /6, π π /2)

None

Text Solution

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The correct answer is:

Here, =

Now, 2 ≤ ≤ x 2 + 2 < ∞ ∞ for all x ∈ ∈ R

⇒ ⇒ > 0 ⇒ ⇒ – < 0

⇒ ⇒ < 1 ⇒ ⇒

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