Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Domain of 
; where {.}denotes the fractional part, is
A
[1, π π )
B
(0, 2 π π ) ~ [1, π π )
C
D
(0, 1)
Text Solution
Verified by ExpertsThe correct answer is:
D
We must have cos(sinx) > 0
⇒ ⇒ π π /2 > sin x ≥ ≥ − − π π /2, which is true for all real x. secondly log x {x} > 0.
If 0 < x < 1 ⇒ ⇒ 0 < {x} < 1 ⇒ ⇒ 0 < x < 1
If x > 1 ⇒ ⇒ {x} ≥ ≥ 1, which is not possible. Thus domain is (0, 1).
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