Published by:
CGP EDU Academic Team
Published on: August 14, 2026
Consider a series of number defined as following
x 0 = 
, x 1 = 
x 2 = 
……. Where
a > 0 then 
x n =
A
B
C
D
Can not be found
Text Solution
Verified by ExpertsThe correct answer is:
B
We have 
= a + x n–1
It is easy to see that the variable x n increases. Let us show that all its values remain less than some constant number we have 
– x n–1 – a < 0 ( x n–1 < x n )
Hence, 
< 0
Since the expression in the second bracket is positive, so we have x n–1 < 
Put 
x n–1 = 
x n = α
From the original relation between x n and x n–1 , we get
α 2 – α – a = 0, α = 
and since α ≥ 0 we have
α = 
.
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