Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let ƒ(x) =
, where n ∈ I and
g (x) =
, then
g [ƒ(x)] is –
Text Solution
Verified by ExpertsThe correct answer is:
A
g [ƒ(x)] = 
∴ g [ƒ (x)] = sin 2 x + 1, x ≠ n π
3, x = n π
R.H.L. =
g [ƒ(0 + h)] =
(sin 2 h + 1) = 1
L.H.L =
g [ƒ(0 – h)] =
(sin 2 h + 1) = 1
∴
g[ƒ (x)] = 1.
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