Published by:
CGP EDU Academic Team
Published on: August 14, 2026
If f(x) = (h 1 (x) –h 1 (–x)) (h 2 (x) – h 2 (–x))……(h 2n+1 (x) – h 2n + 1 (–x))
where h 1 (x), h 2 (x), ……. h n (x) are defined everywhere & f(200) = 0, then f(x) is
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(b, c)
f(–x) = (h 1 (–x)–h 1 (x)) (h 2 (–x) – h 2 (x)) ……
(h 2n+1 (–x) – h 2n+1 (x))
f(–x) = (–1) 2n+1 f(x)
f(x) + f(–x) = 0 ⇒ f(x) is odd
f(–200) = – f(200) = 0
⇒ f(x) is many one
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