If ƒ(x) =
|x| r , where a i ′ s are real constants, then ƒ(x) is-
Text Solution
Verified by ExpertsA
(a, c)
We know that | x | r , r = 0, 1, 2,…. are all continuous every where.
∴ ƒ(x) =
| x | r is every where continuous
Since | x |, | x | 3 , | x | 5 , … are not differentiable at x = 0.
Whereas | x | 2 , | x | 4 , … are every where differentiable.
∴ ƒ(x) =
| x | r is not differentiable at x = 0, if any one of a 1 , a 3 , a 5 , … is non-zero
Thus, for ƒ(x) to be differentiable at x = 0, we must have
a 1 = a 3 = a 5 …. = 0
i.e., a 2k + 1 = 0.
Hence, and are correct answer.
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