Published by:
CGP EDU Academic Team
Published on: August 12, 2026
If 
dx = K sin –1 (ƒ(x)) + c then -
A
ƒ(x) = 
sin (x/ 2)
sin (x/ 2)
B
ƒ(x) = 
cos (x/2), K= 2
cos (x/2), K= 2
C
ƒ(x) = 
tan (x/2), K = 2
tan (x/2), K = 2
D
ƒ(x) = 
sin (x/2), K = 
sin (x/2), K =
Text Solution
Verified by ExpertsThe correct answer is:
A
dx= 
= 
so putting
sin x/2 = t, we have
dx= 
dx
= 2 sin –1 
t + c = 2 sin –1 ( 
sin x/2) + c
So, ƒ(x) = 
sin x/2 and K = 2
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