Published by:
CGP EDU Academic Team
Published on: August 12, 2026
dx = 
log (x 2 + 1) + 
+ 
tan –1 x – A. Then A is equal to -
A
log |x + 1| + c
B
log |x + 1| + c
C
log |x + 1| + c
D
log |x 2 + 1| + c
Text Solution
Verified by ExpertsThe correct answer is:
C
Let I = 
dx, then
I = 
dx
= 
dx + 2 
dx
= I 1 + 2I 2 , where
I 1 = 
dx and I 2 = 
dx
Now, I 1 = 
dx
= 
dx [Using partial fractions]
= 
dx + 
dx –– 
dx
= 
log (x 2 + 1) + 
tan –1 x – 
log |x + 1| + c 1
and, I 2 = 
dx
= 
+ 
tan –1 x + c 2
Hence, I = I 1 + 2I 2
= 
log (x 2 + 1) + 
+ 
tan –1 x – 
log |x + 1| + c.
Hence is the correct answer.
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