Published by:
CGP EDU Academic Team
Published on: August 12, 2026
dx = φ (x) then 
dx =
A
φ (x) + e x .f(x)
B
φ (x) – e x . f(x)
C
{ φ (x) + e x f(x)}
D
{ φ (x) + e x f '(x)}
Text Solution
Verified by ExpertsThe correct answer is:
C
Here 
(f(x) – f '(x)) dx = φ (x)
& 
(f(x) – f '(x)) dx = e x .f(x)
Add ⇒ 2 
. f(x)dx = φ (x) + e x f(x)
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