Published by:
CGP EDU Academic Team
Published on: August 11, 2026
A
x sin –1 x + 
+ c
+ c
B
x sin –1 x – 
+ c
+ c
C
2[x sin –1 x + 
] + c
] + c
D
3[x sin –1 x + 
] + c
] + c
Text Solution
Verified by ExpertsThe correct answer is:
D
Put x = sin θ
dx = cos θ d θ
∴ 
(3sin θ – 4 sin 3 θ ) cos θ d θ
= 
(sin 3 θ ) . cos d θ = 
= 3 [ θ 
– 
= 3 
= 3[ θ sin θ + cos θ ] + c
= 3[x sin –1 x + 
] + c
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