Published by:
CGP EDU Academic Team
Published on: August 11, 2026
Evaluate
dx, where λ n (x) = log e 
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol. We have,
d{ λ (x)} = d(log x) =
dx
d{ λ 2 (x)} = d {log e (log e x)} =
dx =
dx
d{ λ 3 (x)} = d{log (log (log e x)}
= 
=
dx and so on.
∴ d { λ n (x)} = 
Thus,
dx
=
, where t = λ n (x)
= log e (t) + C
= log e { λ n (x)} + C
= λ n+1 (x) + C
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