CGP Edu

Maths Definite Integral and Area Under Curves General Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 12, 2026

Evaluate : dx

None of these

Text Solution

Verified by Experts

The correct answer is:

Let I = dx … (1)

= (By Prop. IV)

= … (2)

Adding (1) and (2), we get

2I = π dx

Put cos x = t

When x = 0 ⇒ t = 1

x = π ⇒ t = –1

∴ 2I = – π

= π

= π tan –1

= π {tan –1 1 – tan –1 (–1)}

= π {2 tan –1 1}

∴ I = π tan –1 1 = π .

Hence I = .

Previous Question Next Question

Get practice questions, solutions, and test series in one place.

Share your experience with this question and solution.

Send your comment, doubt, correction, or feedback to admin.

What students say about this solution

No reviews yet. Be the first to write a review.