Two sides of a parallelogram are along the lines 4x + 5y = 0 and 7x + 2y = 0. If the equation of one of the diagonals of the parallelogram is 11x + 7y = 9, then other diagonal passes through the point:
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Both the lines pass through origin.
point D is equal of intersection of 4x + 5y = 0& 11x + 7y = 9
So, coordinates of point 
Also, point B is point of intersection of 7x + 2y = 0 &11x + 7y = 9
So, coordinates of point 
diagonals of parallelogram intersect at middle
let middle point of 
equation of diagonal AC
y=x
diagonal AC passes through (2,2).
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