Maths Trigonometrical Equations and in Equations, Properties of Triangles, Height and Distance NTA Abhiyas Question Numeric Response
Published on: August 12, 2026

Number of solutions of 2 sin(|x|) = 3 |cosx| in [- , ], is equal to

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The correct answer is:
4

4

In the interval all the values of sin |x|are positive as well as |cos x|

Hence in , equation gets reduced to,

Taking log on both sides,

sin x log 2 = cos x log 3

| tan x| = log 3/ log 2 , value of tan x are positive in 1 st and 3 rd quadrant and negative in 2 nd and 4 th quadrant but positive for |tan x|in allthe values of x in [- , ].

Hence, tan x will repeat its value in all 4 quadrants, so the number of solutions are 4 .

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