Published by:
CGP EDU Academic Team
Published on: August 13, 2026
If 
and the least positive integral value of n such that (z 101 + i 109 ) 106 = z n is k, then the value of 
is equal to
Text Solution
Verified by ExpertsThe correct answer is:
4
(4)
as given that 
this is possible only when n = 4r + 2 and 2n - 2 is a multiple of 3 i.e.,
2 (4r + 2) - 2 is a multiple of 3
i.e., 8r + 2 is a multiple of 3 
r = 2
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