Published by:
CGP EDU Academic Team
Published on: August 14, 2026
The number of ways in which 5 boys and 4 girls can be arranged on a circular table such that no two girls sit together and two particular boys are always together is
Text Solution
Verified by ExpertsThe correct answer is:
A
288
Let two particular boys as one boy, we have only four boys which can be seated at a round table in 3! ways.
The two boys together can be arranged in 2 ways.
So, boys can be seated in 2 x 3! ways.
B 1 B 2 are together. Now 4 girls can be seated at four places (marked x) in 4! ways.
Required number of ways = 3! x 2 x 4!
= 6 x 2 x 24 = 288 ways
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