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CGP EDU Academic Team
Published on: August 14, 2026
If the number of ways of selecting 3 numbers out of 1, 2, 3,…. , 2n + 1 such that they are in arithmetic progression is 441, then the sum of thedivisors of n is equal to
Text Solution
Verified by ExpertsThe correct answer is:
B
32
If a, 6, c are in A. P., then a + c =2b i.e. the sum of two numbers is even
Both numbers are even or odd
Odd numbers 
1,3, 5,......, 2n + 1
(total n + 1 )
Even numbers 
2,4, 6, ......, 2n
(total n )
Required number of ways = n+1 C 2 + n C 2
n+l C 2 + n C 2 = 441
n 2 = 441 
n = 21 = 3 x 7
Sum of divisors = (1 + 3) (1 + 7) = 4 x 8 = 32
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