Home Maths Straight Line NTA Abhiyas Question In an equilateral triangle ABC ', equation o…
Maths Straight Line NTA Abhiyas Question Single Correct MCQ
Published on: August 14, 2026

In an equilateral triangle ABC ', equation of the side BC is x + y -2 = 0 and the centroid of ABC is (0, 0). If points A, B and C are inanticlockwise order, then the equation of side AC is

A
(y + 2) = (2 - ) (x + 2)
B
(y + 2) = (2 + ) (x + 2)
C
(y + 1) = (2 + ) (x + 1)
D
x + 2 = 0

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Text Solution

Verified by Experts
The correct answer is:
B

(y + 2) = (2 + ) (x + 2)

Foot of (0,0) on line BC is D (1,1)

Because (0,0) divides AD internally in the ratio 2 : 1

Hence, by using section formula A = (-2, -2)

Slope of AC is tan (45° +30°) = 2 +

Equation of AC is (y + 2) = (2 + ) (x + 2)

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