Published by:
CGP EDU Academic Team
Published on: August 13, 2026
Let D is a point on the line 
: x + y - 2 = 0 and S (3,3) is a fixed point. The line 
is perpendicular to DS and passes through S. If M is anotherpoint on the line 
(other than D), then the locus of the point of intersection of 
and the angle bisector of the angle MDS is
A
(x + y - 2) 2 = 2(x - 3) 2 + 2(y - 3) 2
B
(x + y - 2) 2 = (x - 3) 2 + (y - 3) 2
C
(x + y - 2) 2 = 
D
None of these
Text Solution
Verified by ExpertsThe correct answer is:
A
( X + y - 2) 2 = 2(x - 3) 2 + 2(y - 3) 2
Let the point of intersection of h and the angle bisector of angle MDS is P (h, k).
Draw perpendicular PF to l 1 from P.
Now, 
PFD & 
PSD are congruent triangles.
Hence,PP = PS
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The distance of the point (-1, l) from the line 12 (x + 6) = 5 (y - 2) is
If the straight line drawn through the point and inclined at an angle with the x - axis meets the…
The line 3x + 2y = 24 meets the y-axis at A & the x-axis at B. The perpendicular bisector of AB mee…
Let in coordinates of vertex A is (0, 0) . Equation of the internal angle bisector of is x + y -1…
The sum of all the values of | | such that the lines x + 2y - 3 = 0, 3x - y –1 = 0 and 2 x + y - …
If the line segment joining P (2,3) and Q (5,7) subtends a right angle at R (x, y) and the area of …