Published by:
CGP EDU Academic Team
Published on: August 13, 2026
The equation of the external bisector of 
BAC of 
ABC with vertices A (5,2), B (2,3) and C (6,5) is
Text Solution
Verified by ExpertsThe correct answer is:
D
x - 2y - 1 = 0
AB = 
AC 
AB = AC 
ABC is an isosceles triangle
Median through A is also an internal angle bisector.
Now, mid-point of B & C is (4,4) = D
The slope of AD is 
So, the slope of external angle bisector of 
BAC is 
Required equation is 
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