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CGP EDU Academic Team
Published on: August 13, 2026
The least value of the quadratic polynomial, f (x) = ( 2p 2 + 1) x 2 + 2 ( 4p 2 –l)x + 4(2p 2 + 1) for real values of p and x is
Text Solution
Verified by ExpertsThe correct answer is:
3
3
y = 2p 2 (x 2 + 4x + 4) + x 2 - 2x + 1 + 3
y = 2p 2 (x + 2) 2 + (x-1) 2 + 3
p=0,x=1
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