Home Maths Conic Sections NTA Abhiyas Question - Parabola Let the normals at points A (4a, - 4a) and B…
Maths Conic Sections NTA Abhiyas Question - Parabola Single Correct MCQ
Published on: August 14, 2026

Let the normals at points A (4a, - 4a) and B (9a, -6a) on the parabola y 2 = 4ax meet at the point P. The equation of the normal from P ony 2 = 4ax (other than PA and PB) is

A
5x + y - 135a = 0
B
5x - y + 115a = 0
C
5x + y + 115 = 0
D
5x - y - 115a = 0

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Text Solution

Verified by Experts
The correct answer is:
A

5x + y - 135a = 0

Let, A = , B =

and the foot of the required normal is , then

2at 1 = -4a, 2at 2 = -6a and t 1 + t 2 + t 3 = 0

t 1 = -2, t 2 = -3 and -2 - 3 + t 3 = 0

t 3 =5

Hence, the equation of the required normal is y = -t 3 x + 2at 3 +

y = -5x + 10a + 125a

y + 5x - 135a = 0

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