The real solutions of the equation are

Maths Inverse Trigonometric Functions NTA Abhiyas Question Single Correct MCQ

Published by: CGP EDU Academic Team

Published on: August 12, 2026

-1,0

0,l

-1, 1

-1, 2

Text Solution

Verified by Experts

The correct answer is:

-1, 0

This equation holds true, if

and

Now,x 2 +x 0 and 0 x 2 +x + l l

x 2 + x 0 and x 2 + x + 1 1 [ x 2 + x + 1 > 0 for all x]

x 2 + x 0 and x 2 + x 0

x 2 +x = 0 x = 0, - 1.

Clearly, these two values satisfy the given equation. Hence, x = — 1, 0 are the solutions of the given equation.

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