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CGP EDU Academic Team
Published on: August 13, 2026
Let a, x, y, z be real numbers satisfying the equations
ax + ay = z
x + ay = z
x + ay = az, where
x, y, z are not all zero, then the number of the possible values of a is
Text Solution
Verified by ExpertsThe correct answer is:
2
2
As x, y, z are not all zero, thus the system has a non-trivial solution.
Thus, D = 0

a (a 2 - a) - a (a - 1) + 1 (a - a) = 0 or a 3 - a 2 - a 2 + a = 0
a (a 2 - 2a + l) = 0
a = 0, 1
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