Published by:
CGP EDU Academic Team
Published on: August 14, 2026
If f (x) is a twice differentiable function such that f" (x) = -f (x), f’(x) = g(x), h (x) = f 2 (x) + g 2 (x) and h (10) = 10, then h (5) is equal to
Text Solution
Verified by ExpertsThe correct answer is:
C
10
h'(x) = 2f.f' + 2gg'
= 2f.f'+2(f')(f")( 
g = f')
= 2f.f' + 2f'(-f) = 0
h’ (x) = 0 
h (x) is a constant function
h(x) = 10
h (5) = 10
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