An urn contains m white and n black balls. A ball is drawn at random and is put back into the urn along with k additional balls of the same colour as that of the ball drawn. A ball is again drawn at random. Then the probability that the ball drawn now is white.
Text Solution
Verified by ExpertsA
Let w 1 → ball drawn in the first draw is white, b 1 → ball drawn in the first drawn in black,
w 2 → ball drawn in the second draw is white. Then P(w 2 ) = P(w 1 ) . P(w 2 / w 1 ) + P(b 1 ) P(w 2 /b 1 )
= 
+ 
= 
= 
= 
──────────────────────────────────────────────────────────────────────────────────────────
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems