Three numbers are chosen at random without replacement from {1, 2, 3,......, 10}. The probability that the minimum of the chosen numbers is 3 or their maximum is 7 is 
then (q – 2p) equals. (Where p & q are co-prime natural numbers)
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Sol. n (S) = ways of selecting 3 number from 10 is 10 C 3
n (E) → n (A ∪ B) where A → min. number chosen is 3
n = 7 C 2
B → max number chosen is 7
n = 6 C 2 also n (A ∩ B) = 3 C 1 = 3
n (E) = 7 C 2 + 6 C 2 – 3 ⇒ P = 
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