In a purse there are 10 coins, all 5 paise except one which is a rupee. In another purse there are 10 coins all 5 paise. 9 coins are taken out from the former purse & put into the latter & then 9 coins are taken out from the latter & put into the former. Then the chance that the rupee is still in the first purse is p then 19p – 9 equals :
Text Solution
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(1)
Sol. 10 coins 9 5 paisa 10 coins 5 paisa
1 1 Rs.
p = p (1 Rs. transfered + Back transfered) + p (1 Rs. not transfered)
× 
+ 
= 
method 2 when 1 Rs coin is in second purse and did not came back in first purse this
prob. = 
× 
= 
⇒ Required probability = 1 – 
= 
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