Suppose that of all used cars of a particular year, 30% have bad brakes. You are considering buying a used car of that year. You take the car to a mechanic to have the brakes checked. The chance that the mechanic will give you wrong report is 20%. Assuming that the car you take to the mechanic is selected " at random" from the population of cars of that year. The odds in favor of chance that the car's brakes are good given that the mechanic says its brakes are good is m : n then (m – 7n) equals. (Where m & n are co-prime natural numbers)
Text Solution
Verified by Experts7
(7)
Sol. Bad brake = 0.3 ; P(E 2 ) = not bad brake = 0.7
mechanic gives correct report P(A 1 ) = 0.8. good brake come → bad brake
given that mechanic says brakes are good

Bad brake Good brake
(0.3) × (0.2) (0.7) (1–0.2)
Probabilty that brakes are good =
=
=
= 
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