A bag contains four tickets marked with numbers 112, 121, 211, 222. One ticket is drawn at random from the bag. Let E i (i = 1, 2, 3) denote the event that ith digit on the ticket is 2. Then
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(a,b,c)E 1 
p first digit is '2' ⇒ 211 or 222 ⇒ P (E 1 ) = 
= 
E 2 
second digit is '2' ⇒ 121, 222 ⇒ P (E 2 ) = 
E 3 
third digit is '2' ⇒ 222 & 112 ⇒ P (E 3 ) = 
(E 1 ∩ E 2 ) = 222 ⇒ P(E 1 ∩ E 2 ) = 
= P (E 1 ) P (E 2 )
Similiarly E 2 & E 3 , E 1 & E 3
also E 1 ∩ E 2 ∩ E 3 → 222 ⇒ P (E 1 ∩ E 2 ∩ E 3 ) = 
≠ P (E 1 ) P (E 2 ) P (E 3 )
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