Published by:
CGP EDU Academic Team
Published on: August 12, 2026
sin − 1 
dx is equal to
A
(a + x) arc tan 
− 
+ C
− + C
B
(a + x) arc tan 
+ 
+ C
+ + C
C
(a – x) arc tan 
− 
+ C
− + C
D
(a + x) arc cot 
− 
+ C
− + C
Text Solution
Verified by ExpertsThe correct answer is:
A
Ι = 
dx put x = a tan 2 θ ⇒ dx = 2a tan θ sec 2 θ d θ
∴ Ι = 
× 2a tan θ sec 2 θ d θ
= 2a 
= 2a 
= 2a 
= a [ θ tan 2 θ – tan θ + θ ] + C = a 
+ C
= (a + x) tan –1 
– 
+ C
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