Find the condition so that the line px + qy = r intersects the ellipse
= 1 in points whose eccentric angles differ by
.
Text Solution
Verified by ExpertsA
a 2 p 2 + b 2 q 2 = r 2 sec 2
= (4 – 2
) r 2
Sol. px + qy = r ....... (1)
+
=1 ....... (2)
P(a cos θ , b sin θ )
Q 
Q 
ap cos θ + qb sin θ = r ......(3)
and
[cos θ – sin θ ] +
[sin θ + cos θ ] = r
pa [cos θ – sin θ ] + qb [sin θ + cos θ ] = r 
pa cos θ + qb sin θ + qb cos θ – pa sin θ = r 
qb cos θ – pa sin θ = r
......(4)
by equation (3) and (4)
a 2 p 2 + q 2 b 2 = r 2 [1 +
] = r 2 [1 + 2 + 1 –
] = r 2
= r 2 sec 2 
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