Published by:
CGP EDU Academic Team
Published on: August 14, 2026
If normal of circle x 2 + y 2 + 6x + 8y + 9 = 0 intersect the parabola y 2 = 4x at P and Q then find the locus of point of intersection of tangent’s at P and Q.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
x + 2y – 3 = 0
Sol.
PQ is chord of contact
T = 0
ky = 2(x + h) ...(1)
above line passes through thecentre ofthe circle i.e. (–3, –4)
–4k = 2(h – 3)
2h + 4k – 6 = 0
x + 2y – 3 = 0
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