If P 1 Q 1 and P 2 Q 2 are two focal chords of the parabola y 2 = 4ax. then the chords P 1 P 2 and Q 1 Q 2 intersect on
Text Solution
Verified by ExpertsB
Let co-ordinate of P 1 and P 2 be
and
then co-ordinate of Q 1 and Q 2 are
and
respectively. ( P 1 Q 1 and P 2 Q 2 are focal chords)
∴ Equation of P 1 P 2 is
y(t 1 + t 2 ) = 2(x + at 1 t 2 ) ...(i)
replacing t 1 by – 1/t then euation of Q 1 Q 2 is

⇒ –y(t 1 + t 2 ) = 2(x t 1 t 2 + a) ...(ii)
adding (i) & (ii) we get
0 = 2(1 + t 1 t 2 )(x + a)
2(1 + t 1 t 2 ) ≠ 0
x + a = 0
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